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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2001

  • question_answer
    A body of mass 10 kg at rest is acted upon simultaneously by two forces 4 N and 3 N at right angles to each other. The kinetic energy of the body at the end of 10 s is:

    A)  100 J                                    

    B)  300 J    

    C)         50 J                       

    D)         20 J

    E)  125J

    Correct Answer: E

    Solution :

    Resultant force, \[F=\sqrt{{{(4)}^{2}}+{{(3)}^{2}}}=5\,N\] Acceleration, \[a=\frac{F}{m}=\frac{5}{10}=0.5\,m{{s}^{-2}}\] Velocity, \[v=0+at=0.5\times 10=5\text{ m/}s\] \[\therefore \] \[KE=\frac{1}{2}m{{v}^{2}}=\frac{1}{2}\times 10\times {{(5)}^{2}}=125\,J\]


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