A) voltage leads the current by\[30{}^\circ \]
B) current leads the voltage by\[30{}^\circ \]
C) current leads the voltage by\[60{}^\circ \]
D) voltage leads the current by\[60{}^\circ \]
E) current and voltage are in phase
Correct Answer: C
Solution :
Net phase difference between current and voltage \[=\frac{\pi }{6}-\left( -\frac{\pi }{6} \right)=\frac{\pi }{3}=60{}^\circ \] Hence, current leads the voltage by\[60{}^\circ \].
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