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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2001

  • question_answer
    A circular thin disc of mass 2 kg has a diameter 0.2 m. Calculate its moment of inertia about an axis  passing  through   the  edge  and perpendicular to the plane of the disc (in\[kg-{{m}^{2}}\]):

    A)  0.01                                      

    B)  0.03                      

    C)  0.02                      

    D)         3

    E)  2

    Correct Answer: B

    Solution :

    \[{{I}_{cm}}=\frac{1}{2}M{{R}^{2}}=\frac{1}{2}\times 2\times {{(0.1)}^{2}}=0.01\,kg-{{m}^{2}}\] About an axis passing through the edge \[I={{I}_{cm}}+M{{R}^{2}}\] (Theorem of \[|\,\,|\]axis)                 \[=0.01+2\times {{(0.1)}^{2}}\]                 \[=0.03\,kg-{{m}^{2}}\]


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