A) \[AgN{{O}_{3}}+NaBr\xrightarrow{{}}AgBr+NaN{{O}_{3}}\]
B) \[AgBr+2N{{a}_{2}}{{S}_{2}}{{O}_{3}}\xrightarrow{{}}\]\[N{{a}_{3}}[Ag{{({{S}_{2}}{{O}_{3}})}_{2}}]+NaBr\]
C) \[AgBr+hv\xrightarrow[{}]{{}}AgB{{r}^{*}}\]
D) \[{{C}_{6}}{{H}_{4}}{{(OH)}_{2}}+2AgB{{r}^{*}}\xrightarrow[{}]{{}}{{C}_{6}}{{H}_{4}}{{O}_{2}}\] \[+2HBr+2Ag\]
E) \[AgBr+2N{{H}_{3}}\xrightarrow[{}]{{}}[Ag{{(N{{H}_{3}})}_{2}}]Br\]
Correct Answer: D
Solution :
\[\underset{quinol}{\mathop{{{C}_{6}}{{H}_{4}}{{(OH)}_{2}}}}\,+2AgB{{r}^{*}}\] \[\xrightarrow[{}]{{}}\underset{quinone}{\mathop{{{C}_{6}}{{H}_{4}}{{O}_{2}}}}\,+2HBr+2Ag\] reaction represents developing in photography. Because in developing in photography quinol \[{{C}_{6}}{{H}_{4}}{{(OH)}_{2}}\]is used as mild reducing agent to reduce more silver bromide to silver. It is done to make silver visible.
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