A) \[{{x}^{2}}+{{y}^{2}}\]
B) \[\sqrt{{{x}^{2}}+{{y}^{2}}}\]
C) \[x+iy\]
D) \[x-iy\]
E) \[\sqrt{{{x}^{2}}-{{y}^{2}}}\]
Correct Answer: D
Solution :
\[\because \] \[\sqrt{a+ib}=x+iy\] \[\therefore \] \[\sqrt{a-ib}=x-iy\]
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