CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2002

  • question_answer
    If the progression 3, 10, 17, ... and 63, 65, 67,... are such that their n th term are equal, then n is equal to:

    A)  13         

    B)                         15

    C)                         9                                            

    D)                         8

    E)                         11

    Correct Answer: A

    Solution :

                    nth term of first series\[=3+(n-1)7\] \[=7n-4\] and nth term of second series\[=63+{{(n-1)}^{2}}\] \[=2n+61\] According to question, \[7n-4=2n+61\] \[\Rightarrow \]               \[5n=65\] \[\Rightarrow \]               \[n=13\]              


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