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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2002

  • question_answer
    The equation of the plane passing through the intersection of the planes\[x+2y+3z+4=0\] and\[4x+3y+2z+1=0\]and the origin is:

    A)  \[3x+2y+z+1=0\]

    B)                         \[3x+2y+z=0\]

    C)                         \[2x+3y+\text{ }z=0\]

    D)                         \[x+y+z=0\]

    E)                         none of the above

    Correct Answer: B

    Solution :

    The equation of plane passing through the intersection of given planes is \[(x+2y+3z+4)+\lambda (4x+3y+2z+1)=0\] \[\because \]It passes through the origin, then \[4+\lambda =0\] \[\lambda =-4\] \[\therefore \]Required equation is \[(x+2y+3z+4)-4(4x+3y+2z+1)=0\] \[\Rightarrow \]\[3x+2y+z=0\]


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