2. Solved Papers
  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2002

  • question_answer
    The projection of the vector\[\hat{i}+\hat{j}+\hat{k}\]along the vector\[\hat{j}\] is:

    A)  1    

    B)                         0

    C)                         2                                            

    D)                         \[-1\]

    E)                         \[-2\]

    Correct Answer: A

    Solution :

         The projection of\[\hat{i}+\hat{j}+\hat{k}\]along \[\hat{j}\] \[=\frac{(\hat{i}+\hat{j}+\hat{k}).\hat{j}}{\sqrt{1+0+0}}=1\]                      


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