A) \[\frac{512}{105}\]
B) \[\frac{105}{512}\]
C) \[\frac{100}{513}\]
D) \[^{10}{{C}_{6}}\]
E) \[^{10}{{C}_{4}}\,\times 6!\]
Correct Answer: B
Solution :
Probability of getting a head\[=\frac{1}{2}\] \[\therefore \]Required probability\[{{=}^{10}}{{C}_{6}}{{\left( \frac{1}{2} \right)}^{6}}{{\left( \frac{1}{2} \right)}^{4}}\] \[=\frac{10.9.8.7}{1.2.3.4}\times \frac{1}{{{(2)}^{10}}}\] \[=\frac{105}{512}\]
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