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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2002

  • question_answer
    A ball of mass 0.5 kg moving with a velocity of \[2\text{ }m{{s}^{-1}}\]strikes a wall normally and bounces back with the same speed. If the time of contact between the ball and wall is\[{{10}^{-3}}s,\] the average force exerted by the wall on the ball is:

    A)  1125N                                 

    B)  1000 N

    C)         500 N                   

    D)         2000 N

    E)  5000 N

    Correct Answer: D

    Solution :

    Impulse \[=mv-(-mv)\] \[=0.5\times 2-(-0.5\times 2)=2\] Hence, \[F=\frac{2}{{{10}^{-3}}}=2000\text{ }N\]


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