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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2002

  • question_answer
    A point moves such that the area of the triangle formed by it with the points (1, 5) and \[(3,-7)\]is 21 sq unit. Then locus of the point is:

    A)  \[6x+y-32=0\]  

    B)         \[6x-y+32=0\]

    C)         \[x+6y-32=0\]  

    D)         \[6x-y-32=0\]

    E)         none of these

    Correct Answer: A

    Solution :

    Let\[(x,\text{ }y)\]be the required point \[\therefore \]  \[\frac{1}{2}\left| \begin{matrix}    x & y & 1  \\    1 & 5 & 1  \\    3 & -7 & 1  \\ \end{matrix} \right|=21\] \[\Rightarrow \]\[x(5+7)-y(1-3)+1(-7-15)=42\] \[\Rightarrow \]               \[12x+2y+22=42\] \[\Rightarrow \]               \[12x+2y-64=0\] \[\Rightarrow \]               \[6x+y-32=0\]


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