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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2002

  • question_answer
    If\[tan\text{ }A+cot\text{ }A=4,\]then\[ta{{n}^{4}}A+co{{t}^{4}}A\]is equal to:

    A)  110                                       

    B)         191

    C)         80                                         

    D)         194

    E)         195

    Correct Answer: D

    Solution :

    We have \[tan\text{ }A+cot\text{ }A=4\] On squaring both sides, we get \[ta{{n}^{2}}A+co{{t}^{2}}A+2=16\] \[\Rightarrow \]               \[ta{{n}^{2}}A+co{{t}^{2}}A=16-2=14\] Again squaring, we get       \[ta{{n}^{4}}A+co{{t}^{4}}A+2=196\] \[\Rightarrow \] \[ta{{n}^{4}}A+co{{t}^{4}}A=196-2=194\]


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