A) \[6x+y-32=0\]
B) \[6x-y+32=0\]
C) \[x+6y-32=0\]
D) \[6x-y-32=0\]
E) none of these
Correct Answer: A
Solution :
Let\[(x,\text{ }y)\]be the required point \[\therefore \] \[\frac{1}{2}\left| \begin{matrix} x & y & 1 \\ 1 & 5 & 1 \\ 3 & -7 & 1 \\ \end{matrix} \right|=21\] \[\Rightarrow \]\[x(5+7)-y(1-3)+1(-7-15)=42\] \[\Rightarrow \] \[12x+2y+22=42\] \[\Rightarrow \] \[12x+2y-64=0\] \[\Rightarrow \] \[6x+y-32=0\]You need to login to perform this action.
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