2. Solved Papers
  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2002

  • question_answer
    If \[x\sin 45{}^\circ {{\cos }^{2}}60{}^\circ =\frac{{{\tan }^{2}}60{}^\circ \cos ec30{}^\circ }{\sec 45{}^\circ {{\cot }^{2}}30{}^\circ }\]then\[x\]is equal to:

    A)  2                                            

    B)         4

    C)         8                                            

    D)         16

    E)         32

    Correct Answer: C

    Solution :

    \[x.\frac{1}{\sqrt{2}}.\frac{1}{4}=\frac{{{(\sqrt{3})}^{2}}.2}{\sqrt{2}{{(\sqrt{3})}^{2}}}\] \[\Rightarrow \]               \[x=8\]


You need to login to perform this action.
You will be redirected in 3 sec spinner