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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2002

  • question_answer
    An electric motor operates on a 50 V supply and a current of 12 A. If the efficiency of the motor is 30%, what is the resistance of the winding of the motor?

    A)  \[6\,\Omega \]                               

    B)  \[4\,\Omega \]               

    C)  \[2.9\,\Omega \]            

    D)         \[3.1\,\Omega \]

    E)  \[2.5\,\Omega \]

    Correct Answer: C

    Solution :

    \[I=\frac{E-e}{R}\]                                             ...(1) and        \[\eta \times 100=\left( \frac{e}{E} \right)\times 100\]               ...(2) \[\therefore \]  \[30=\frac{e}{50}\times 100\]               (from Eqs. (2)) \[\Rightarrow \]                   \[e=15V\] Thus,     \[R=\frac{50-15}{12}=2.9\,\Omega \]


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