2. Solved Papers
  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2002

  • question_answer
    A quarter horse power motor runs at a speed of 600 rpm. Assuming 40% efficiency the work done by the motor in one rotation will be:

    A)  7.46 J                   

    B)         7400 J  

    C)         7.46 erg              

    D)         74.6 J

    E)  746 J

    Correct Answer: A

    Solution :

    \[P\times 40%=\frac{W}{t}\Rightarrow \frac{746}{4}\times \frac{40}{100}\left( \frac{W}{2\pi \times \frac{600\times 2\pi }{60}} \right)\] \[\therefore \]  \[W=7.46\,J\]


You need to login to perform this action.
You will be redirected in 3 sec spinner