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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2002

  • question_answer
    A person carrying a whistle emitting continuously a note of 272 Hz is running towards a reflecting surface with a speed of 18 km/h. The speed of sound in air is 345\[m{{s}^{-1}}\]. The number of beats heard by him is:

    A)  4                            

    B)  6                            

    C)  8                            

    D)         3

    E)  zero

    Correct Answer: C

    Solution :

    \[n=n\left( \frac{v+{{v}_{o}}}{v-{{v}_{s}}} \right)=272\left( \frac{345+5}{345-5} \right)\] \[(\because {{v}_{o}}={{v}_{s}}=18\,km/s=5\,m/s)\] \[\Rightarrow \]               \[n=280\] \[\therefore \]  \[Beats=n-n=8\]


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