CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2002

  • question_answer
    In the\[HCl\]molecule, the separation between the nuclei of the two atoms is about \[1.27\overset{\text{o}}{\mathop{\text{A}}}\,\]  \[(1\overset{\text{o}}{\mathop{\text{A}}}\,={{10}^{-10}})\]. The approximate location of the centre of mass of the molecule, assuming the chlorine atom to be about 35.5 times as massive as hydrogen is:

    A) \[1\overset{\text{o}}{\mathop{\text{A}}}\,\]

    B)         \[2.5\overset{\text{o}}{\mathop{\text{A}}}\,\]

    C)         \[1.24\overset{\text{o}}{\mathop{\text{A}}}\,\]

    D)        \[1.5\overset{\text{o}}{\mathop{\text{A}}}\,\]

    E)                 \[0.9\overset{\text{o}}{\mathop{\text{A}}}\,\]

    Correct Answer: C

    Solution :

                             \[{{r}_{cm}}=\frac{{{m}_{H}}\times {{r}_{H}}+{{m}_{Cl}}+{{r}_{Cl}}}{{{m}_{H}}+{{m}_{Cl}}}\] \[=\frac{{{m}_{H}}\times 0+35.5\,{{m}_{H}}+{{r}_{Cl}}}{{{m}_{H}}+{{m}_{Cl}}}\] \[=1.24{\AA}\] (from chlorine atom)


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