CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2002

  • question_answer
    A uniform plank of Youngs modulus Y is moved over a smooth horizontal surface by a constant horizontal force F. The area of cross-section of the plank is A. The compressive strain on the plank in the direction of the force is:

    A)  \[\frac{F}{AY}\]                                               

    B)  \[\frac{2F}{AY}\]            

    C)  \[\frac{1}{2}\frac{F}{AY}\]          

    D)         \[\frac{3F}{AY}\]

    E)  \[\frac{F}{3AY}\]

    Correct Answer: C

    Solution :

    Not available


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