CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2002

  • question_answer
    A sphere of mass 10 kg and radius 0.5 m rotates about a tangent. The moment of inertia of the sphere is:

    A)  \[5kg-{{m}^{2}}\]       

    B)                         \[2.7kg-{{m}^{2}}\]       

    C)         \[3.5kg-{{m}^{2}}\]     

    D)         \[4.5\text{ }kg-{{m}^{2}}\]

    E)  \[4kg-{{m}^{2}}\]

    Correct Answer: C

    Solution :

    Moment of inertia of sphere about tangent \[I=\frac{2}{5}M{{R}^{2}}+M{{R}^{2}}=\frac{7}{5}M{{R}^{2}}\]                 \[=\frac{7}{5}\times 10\times {{(0.5)}^{2}}=3.5\,kg-{{m}^{2}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner