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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2002

  • question_answer
    The rate of emission of a black body at\[0{}^\circ C\]is R, its rate of emission at\[273{}^\circ C\]is:

    A)  4R                         

    B)         8R                         

    C)  16 R                      

    D)         32 R

    E)  10 R

    Correct Answer: C

    Solution :

    \[R\propto {{T}^{4}}\] \[\therefore \]  \[\frac{R}{R}=\frac{{{(273+273)}^{4}}}{{{(273+0)}^{4}}}=\frac{16\times {{(273)}^{4}}}{{{(273)}^{4}}}\] \[\Rightarrow \]               \[R=16R\]


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