A) sp -hybridization
B) \[s{{p}^{2}}-\]hybridization
C) \[s{{p}^{3}}-\]hybridization
D) \[s{{p}^{3}}d-\]hybridization
E) \[s{{p}^{3}}{{d}^{2}}-\]hybridization
Correct Answer: A
Solution :
Carbon of\[CH\equiv CH\]or\[{{C}_{2}}{{H}_{5}}\]has sp- hybridization.
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