question_answer

A straight line through P (1, 2) is such that its intercept between the axes is bisected at P. Its equation is:

A)  \[x+y=-1\]         

B)  \[x+y=3\]

C)  \[x+2y=5\]     

D)         \[2x+y=4\]

E)  none of these

Correct Answer: E

Solution :

\[\because \]P (1, 2) is midpoint of AB, therefore co-ordinate of A and B respectively (2, 0) and (0, 4) \[\therefore \]Equation of line AB is \[y-0=\frac{4}{-2}(x-4)\] \[\Rightarrow \]               \[2x+y=8\]