• # question_answer An object of mass m falls on to a spring of constant k from h. Then the spring undergoes compression by a length$x$. The maximum compression x is given by the equation: A)  $mgh=\frac{1}{2}k{{x}^{2}}$B)  $mgh(h+x)=\frac{1}{2}k{{x}^{2}}$C)  $mg(h+x)=-kx$D)  $mgh=-kx$E)  $mgh=-\frac{1}{2}k{{x}^{2}}$

Conservation of energy yields $mgh+mgx=\frac{1}{2}k{{x}^{2}}$ $\Rightarrow$               $mg(h+x)=\frac{1}{2}k{{x}^{2}}$