A) (1/4, 0)
B) (1, 2)
C) (5/4, 1)
D) (3/4, 5/2)
E) (1, 5/4)
Correct Answer: C
Solution :
The equation of parabola is \[{{y}^{2}}-x-2y+2=0\] \[\Rightarrow \] \[{{(y-1)}^{2}}=x-1\] Let\[y-1=y\]and \[x-1=X\] \[\therefore \] \[{{Y}^{2}}=X\] Here, \[a=\frac{1}{4}\] \[\therefore \]Focus of\[{{Y}^{2}}=X\]is \[\left( \frac{1}{4},0 \right)\] \[\therefore \] \[x-1=\frac{1}{4}\]and \[y-1=0\] \[\Rightarrow \] \[x=\frac{5}{4}\]and\[y=1\] \[\therefore \]Focus of given parabola \[=\left( \frac{5}{4},1 \right)\]
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