CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2003

  • question_answer
    The point on the curve\[x{{y}^{2}}=1\]that is nearest to the origin, is:

    A)  (1, 1)

    B)  (4, 1/2)

    C)  (1/4, 2)

    D)  \[({{2}^{1/6}},{{(1/2)}^{1/12}})\]

    E)  \[({{(1/2)}^{1/3}},{{2}^{1/6}})\]

    Correct Answer: E

    Solution :

    The point\[\left[ {{\left( \frac{1}{2} \right)}^{1/3}},{{2}^{1/6}} \right]\]on the curve\[x{{y}^{2}}=1\]is nearest to the origin.


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