CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2003

  • question_answer
    An elastic ball is dropped from a height h and it rebounds many times from the floor. If the coefficient of restitution is e, the time interval between the second and the third impact, is:

    A)  \[ev/g\]             

    B)         \[{{e}^{2}}v/g\]              

    C)         \[{{e}^{2}}\sqrt{\left( \frac{8h}{g} \right)}\]      

    D)         \[{{e}^{2}}\sqrt{\left( \frac{h}{g} \right)}\]

    E)  \[{{e}^{2}}\sqrt{\left( \frac{2h}{g} \right)}\]

    Correct Answer: C

    Solution :

    \[t=\sqrt{\left( \frac{2h}{g} \right)}\]                                      ?.. (1) The second impact occurs after an additional time \[=2\sqrt{2{{h}_{1}}g}=2e\sqrt{\frac{2h}{g}}\] \[\therefore \]The third impact occurs after an additional time                 \[=2\sqrt{2{{h}_{2}}g}\]                 \[=2{{e}^{2}}\sqrt{\frac{2h}{g}}\]                 \[={{e}^{2}}\sqrt{\frac{8h}{g}}\]


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