CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2003

  • question_answer
    \[\int{{{e}^{-\log x}}}dx\]is equal to:

    A)  \[{{e}^{-\log x}}+c\]                      

    B)  \[-x{{e}^{-\log x}}+c\]  

    C)         \[{{e}^{\log x}}+c\]       

    D)         \[\log x+c\]

    E)  \[\log |x|+c\]

    Correct Answer: E

    Solution :

    \[\int{{{e}^{-\log x}}}dx\] \[=\int{{{e}^{\log 1/x}}}dx=\int{\frac{1}{x}}dx\] \[=\log |x|+c\]


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