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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2003

  • question_answer
    If the third term of a GP is P, then the product of the first 5 terms of the GP is:

    A)  \[{{P}^{3}}\]                                     

    B)  \[{{P}^{2}}\]                     

    C)  \[{{P}^{10}}\]                   

    D)         \[{{P}^{4}}\]

    E)  \[{{P}^{5}}\]

    Correct Answer: E

    Solution :

    Let first term and common difference of GP be a and r respectively. \[\therefore \]  \[a{{r}^{2}}=P\] Now,     \[a.ar.a{{r}^{2}}.a{{r}^{3}}.a{{r}^{4}}\]                 \[={{a}^{2}}{{r}^{10}}={{(a{{r}^{2}})}^{5}}={{p}^{5}}\]


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