• # question_answer For non-singular square matrices A, B and C of the same order,${{(A{{B}^{-1}}C)}^{-1}}$is equal to: A)  ${{A}^{-1}}B{{C}^{-1}}$                             B)  ${{C}^{-1}}{{B}^{-1}}{{A}^{-1}}$            C)  $CB{{A}^{-1}}$              D)         ${{C}^{-1}}B{{A}^{-1}}$E)  ${{C}^{-1}}BA$

Correct Answer: D

Solution :

${{(A{{B}^{-1}}C)}^{-1}}$ $={{C}^{-1}}{{({{B}^{-1}})}^{-1}}{{A}^{-1}}={{C}^{-1}}B{{A}^{-1}}$

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