A) imaginary
B) rational and equal
C) rational and distinct
D) irrational
E) real, may be rational or irrational
Correct Answer: C
Solution :
\[\because \]a, b, care in AP \[\Rightarrow \] \[2b=a+c\] ...(i) Now, \[D=4{{b}^{2}}-4ac\] \[={{(a+c)}^{2}}-4ac\] \[={{(a-c)}^{2}}\ge 0\] Roots of the given equation are rational and distinct.You need to login to perform this action.
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