A) \[a=-1,b=-1,c=2\]
B) \[a=1,b=-1,c=0\]
C) \[a=-1,b=-1,c=0\]
D) \[a=1,b=1,c=0\]
E) \[a=-1,b=-1,c=1\]
Correct Answer: B
Solution :
Since, the co-ordinates of three vertices A, B and C are\[\left( \frac{5}{3},-\frac{4}{3} \right),(0,0)\]and\[\left( -\frac{2}{3},\frac{7}{3} \right)\] respectively, also the midpoint of AC is\[\left( \frac{1}{2},\frac{1}{2} \right)\], therefore the equation of line passing through\[\left( \frac{1}{2},\frac{1}{2} \right)\]and (0,0) is given by \[x-y=0,\]which is the required equation of another diagonal, so \[a=1,\text{ }b=-1\]and\[c=0\].
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