CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2003

  • question_answer
    If\[a=\hat{i}+2\hat{j}+3\hat{k},\]and \[\overrightarrow{b}=\hat{i}\times (\overrightarrow{a}\times \hat{i})+\hat{j}\times (\overrightarrow{a}\times \hat{j})+\overrightarrow{k}\times (\overrightarrow{a}\times \hat{k}),\] then length of \[\vec{b}\] is equal to

    A)  \[\sqrt{12}\]     

    B)         \[2\sqrt{12}\]

    C)  \[3\sqrt{14}\]  

    D)         \[3\sqrt{12}\]

    E)                                 \[2\sqrt{14}\]

    Correct Answer: E

    Solution :

    \[\overrightarrow{a}=\hat{i}+2\hat{j}+3\hat{k}\]and \[\overrightarrow{b}=\hat{i}\times (\overrightarrow{a}\times \hat{i})+\hat{j}\times (\overrightarrow{a}\times \hat{j})+\hat{k}\times (\overrightarrow{a}\times \hat{k})\] \[=3\overrightarrow{a}-\overrightarrow{a}=2\overrightarrow{a}\] \[=2(\hat{i}+2\hat{j}+3\hat{k})\] \[\Rightarrow \]               \[|\overrightarrow{b}|=\sqrt{4+16+36}\]                 \[=\sqrt{56}\]                 \[=2\sqrt{14}\]


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