A) 3, 7
B) \[-3,7\]
C) \[-3,-7\]
D) \[3,10\]
E) \[-3,-10\]
Correct Answer: E
Solution :
The given equation is \[{{x}^{2}}+17x+q=0\] \[\therefore \]Product of roots\[=(-2)(-15)=q\] \[\Rightarrow \] \[q=30\] \[\therefore \]Original equation is \[{{x}^{2}}+13x+30=0\] \[\Rightarrow \] \[{{x}^{2}}+10x+3x+30=0\] \[\Rightarrow \] \[(x+10)(x+3)=0\] \[\Rightarrow \] \[x=-10,-3\]You need to login to perform this action.
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