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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2003

  • question_answer
    An electric bulb is marked 100 W, 230 V. If the supply voltage drops to 115 V, what is the total energy produced by the bulb in 10 min?

    A)  30 kJ                    

    B)         20 kJ    

    C)  15 kJ                    

    D)  10 kJ

    E)  5kJ

    Correct Answer: C

    Solution :

    \[R=\frac{230\times 230}{100}=529\,\Omega \] \[\therefore \]  \[H=\frac{{{V}^{2}}}{R}\times t\]                 \[=\frac{115\times 115}{529}\times 10\times 60\] \[=15kJ\]


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