A) \[40\,\mu F\]
B) \[20\,\mu F\]
C) \[13.3\,\mu F\]
D) \[10\,\mu F\]
E) \[2.5\,\mu F\]
Correct Answer: C
Solution :
The net capacitance of capacitors in series combination\[\frac{1}{C}=\frac{1}{10}+\frac{1}{10}+\frac{1}{10}\] \[\Rightarrow \] \[C=\frac{10}{3}\mu F\] Equivalent capacitance of the circuit \[C=10+\frac{10}{3}=\frac{40}{3}\] \[=13.3\,\mu F\]
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