2. Solved Papers
  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2003

  • question_answer
    The coefficient of mutual inductance between the primary and secondary of the coil is 5 H. A current of 10 A is cut off in 0.5 s. The induced emf is:

    A)  1 V                        

    B)         10 V

    C)  5 V                        

    D)         100 V

    E)  50V

    Correct Answer: D

    Solution :

    \[e=\frac{Ldi}{dt}=\frac{5\times 10}{0.5}=100\,V\]


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