A) \[16:25\]
B) \[9:1\]
C) \[1:9\]
D) \[25:16\]
E) \[5:4\]
Correct Answer: A
Solution :
\[\frac{{{I}_{\min }}}{{{I}_{\max }}}=\frac{{{(\sqrt{{{I}_{1}}}-\sqrt{{{I}_{2}}})}^{2}}}{{{(\sqrt{{{I}_{1}}}+\sqrt{{{I}_{2}}})}^{2}}}\] \[=\frac{{{(\sqrt{81I}-\sqrt{I})}^{2}}}{{{(\sqrt{81I}+\sqrt{I})}^{2}}}\] \[=\frac{{{(8\sqrt{I})}^{2}}}{{{(10\sqrt{I})}^{2}}}=\frac{16}{25}\]
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