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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2003

  • question_answer
    An automobile in travelling at 50 km/h, can be stopped at a distance of 40 m by applying brakes. If the same automobile is travelling at 90 km/h, all other conditions remaining same and assuming no skidding, the minimum stopping distance in metres is:

    A)  72                         

    B)         92.5                      

    C)  102.6                   

    D)         129.6

    E)  139.6

    Correct Answer: D

    Solution :

    \[s\propto {{u}^{2}}\] \[\Rightarrow \]               \[\frac{{{s}_{2}}}{40}={{\left( \frac{90\times \frac{5}{18}}{50\times \frac{5}{18}} \right)}^{2}}\] \[\Rightarrow \]               \[{{s}_{2}}=129.6\,m\]


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