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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2003

  • question_answer
    A charged oil drop of mass \[9.75\times {{10}^{-15}}kg\] and charge\[30\times {{10}^{-16}}C\]is suspended in a uniform electric field existing between two parallel plates. The field between the plates, taking \[(g=10\text{ }m{{s}^{-2}})\]is:

    A)  3.25 V/m            

    B)         300 V/m             

    C)         325 V/m             

    D)         32.5 V/m

    E)  3000 V/m

    Correct Answer: D

    Solution :

    In equilibrium \[eE=mg\] \[\Rightarrow \]               \[E=\frac{mg}{e}\]                 \[=\frac{9.75\times {{10}^{-15}}\times 10}{30\times {{10}^{-16}}}\]                 \[=32.5\,V/m\]


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