CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2003

  • question_answer
    Two radioactive nuclides\[x\]and y have half-lives 1 h and 2 h respectively. Initially the samples have equal number of nuclei. After 4 h the ratio of the numbers of\[x\]and y is:

    A)  \[\frac{1}{2}\]                  

    B)         2

    C)  \[\frac{1}{4}\]

    D)  1

    E)  \[\frac{1}{16}\]

    Correct Answer: C

    Solution :

    \[\frac{{{N}_{1}}}{{{N}_{2}}}=\frac{{{(1/2)}^{4/1}}}{{{(1/2)}^{4/2}}}=\frac{(1/16)}{(1/4)}=\frac{1}{4}\]


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