2. Solved Papers
  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2003

  • question_answer
    \[_{92}{{U}^{238}}\]decays successively to from\[_{90}T{{h}^{234}},\]\[_{91}P{{a}^{234}}{{,}_{92}}{{U}^{234}}{{,}_{90}}T{{h}^{230}}{{,}_{88}}R{{a}^{226}}\]during the reaction the number of\[\alpha -\]particles emitted is:

    A)  4                            

    B)         3                            

    C)  5                            

    D)         2

    E)  1

    Correct Answer: B

    Solution :

    Decrease in mass number \[=238-226=12\] \[\therefore \]Number of \[\alpha \]-particles emitted\[=\frac{12}{4}=3\]


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