CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2003

  • question_answer
    Paramagnetism of oxygen is explained on the basis of its electronic configuration of:

    A)  \[{{({{\pi }^{*}}2{{p}_{x}})}^{1}}{{(\pi 2{{p}_{y}})}^{1}}\]             

    B)  \[{{({{\pi }^{*}}2{{p}_{y}})}^{1}}{{({{\pi }^{*}}2{{p}_{z}})}^{1}}\]

    C)  \[{{({{\sigma }^{*}}2s)}^{1}}{{(\pi 2{{p}_{y}})}^{1}}\]     

    D)  \[{{({{\sigma }^{*}}2s)}^{1}}{{(\pi 2{{p}_{y}})}^{1}}\]

    E)  \[{{(\pi 2{{p}_{x}})}^{1}}{{(\pi 2{{p}_{y}})}^{1}}\]

    Correct Answer: B

    Solution :

    The molecular electronic configuration of\[{{O}_{2}}\]is: \[{{O}_{2}}=[KK{{(\sigma 2s)}^{2}}{{({{\sigma }^{*}}2s)}^{2}}{{(\sigma 2{{p}_{x}})}^{2}}{{(\pi 2{{p}_{y}})}^{2}}\] \[{{(\pi 2{{p}_{z}})}^{2}}{{({{\pi }^{*}}2{{p}_{y}})}^{1}}{{({{\pi }^{*}}2{{p}_{z}})}^{1}}]\]


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