A) \[42\text{ }J\text{ }mo{{l}^{-1}}{{K}^{-1}}\]
B) \[21\text{ }J\text{ }mo{{l}^{-1}}{{K}^{-1}}\]
C) \[84\text{ }J\text{ m}o{{l}^{-1}}{{K}^{-1}}\]
D) \[8.4\text{ }J\text{ mo}{{l}^{-1}}{{K}^{-1}}\]
E) \[0.028\text{ }J\text{ }mo{{l}^{-1}}{{K}^{-1}}\]
Correct Answer: D
Solution :
The entropy change for the vaporization of water to steam is given by \[\Delta S=\frac{\Delta {{H}_{vap}}}{T}\] \[\Delta H=840\,J\,mo{{l}^{-1}}\] \[T=-173+273=100{}^\circ K\] \[\Delta S=\frac{\Delta H}{T}\] \[\Delta S=\frac{840}{100}=8.4\,J\,mo{{l}^{-1}}{{K}^{-1}}\]
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