A) \[2.6\times {{10}^{-9}}\]
B) \[4\times {{10}^{-8}}\]
C) \[8\times {{10}^{-12}}\]
D) \[3.2\times {{10}^{-11}}\]
E) \[8\times {{10}^{-10}}\]
Correct Answer: D
Solution :
Solubility of \[Ca{{F}_{2}}=2\times {{10}^{-4}}mol\,{{L}^{-1}}\] Each mole of\[Ca{{F}_{2}}\]dissolving in\[{{H}_{2}}O\]gives one mole of\[C{{a}^{2+}}\]and two moles of\[{{F}^{-}}\]ions. \[Ca{{F}_{2}}C{{a}^{2+}}+2{{F}^{-}}\] \[2\times {{10}^{-4}}M.2\times 2\times {{10}^{-4}}M\] \[{{K}_{sp}}=[C{{a}^{2+}}]{{[{{F}^{-}}]}^{2}}\] \[=[2\times {{10}^{-4}}]{{[2\times 2\times {{10}^{-4}}]}^{2}}\] \[{{K}_{sp}}=3.2\times {{10}^{-11}}\]
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