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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2004

  • question_answer
    If\[\int_{-1/2}^{1/2}{\cos x\log \left( \frac{1+x}{1-x} \right)}dx=k.\log 2,\]then\[k\]equals to:

    A)  0                                            

    B)  \[-1\]

    C)  \[-2\]                   

    D)         \[\frac{1}{2}\]

    E)  \[-\frac{1}{2}\]

    Correct Answer: A

    Solution :

    \[\because \]\[\cos x\log \left( \frac{1+x}{1-x} \right)\]is an odd function. \[\therefore \] \[\int_{-1/2}^{1/2}{\cos x\log \left( \frac{1+x}{1-x} \right)}dx=0\] \[\therefore \]  \[k=0\]


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