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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2004

  • question_answer
    The potential at a point P which is forming a corner of a square of side 93 mm with charges,\[{{Q}_{1}}=33\text{ }nC,{{Q}_{2}}=-51\text{ }nC,{{Q}_{3}}=47\text{ }nC\] located at the other three comers is nearly:

    A)  16 kV          

    B)                         4 kV                  

    C)  400V                    

    D)         160V

    E)  16V

    Correct Answer: B

    Solution :

    \[V=\frac{1}{4\pi {{\varepsilon }_{0}}}\left( \frac{{{Q}_{1}}}{{{r}_{1}}}+\frac{{{Q}_{2}}}{{{r}_{2}}}+\frac{{{Q}_{3}}}{{{r}_{3}}} \right)\] \[=\frac{1}{4\pi {{\varepsilon }_{0}}}\left( \frac{33\times {{10}^{-9}}}{93\times {{10}^{-3}}}-\frac{51\times {{10}^{-9}}}{\sqrt{2}\times 93\times {{10}^{-3}}} \right.\]\[+\left. \frac{47\times {{10}^{-9}}}{93\times {{10}^{-3}}} \right)\] \[=\frac{1}{4\pi {{\varepsilon }_{0}}}\times \frac{{{10}^{-9}}}{93\times {{10}^{-3}}}\left( 33-\frac{51}{\sqrt{2}}+47 \right)\] \[\approx 4\times 1000\,V=4\,kV\]


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