CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2004

  • question_answer
    The area between the curves\[y=x{{e}^{x}}\]and\[y=x{{e}^{-x}}\]and the line\[x=1,\]in sq unit, is:

    A)  \[2\left( e+\frac{1}{e} \right)sq\,unit\]

    B)  \[0\text{ }sq\text{ }unit\]

    C)  \[2e\,sq\text{ }unit\]

    D)  \[\frac{2}{e}\,sq\text{ }unit\]

    E)  \[2\left( e-\frac{1}{e} \right)\,sq\text{ }unit\]

    Correct Answer: D

    Solution :

    Required area\[=\int_{0}^{1}{(x{{e}^{x}}-x{{e}^{-x}})}\,dx\] \[=[x{{e}^{x}}-{{x}^{x}}+x{{e}^{-x}}+{{e}^{-x}}]_{0}^{1}\]                 \[=e-e+\frac{1}{e}+\frac{1}{e}=\frac{2}{e}sq\text{ }unit\]


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