CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2004

  • question_answer
    The solution of\[\frac{dy}{dx}=\frac{ax+h}{by+k}\]represents a parabola, when:

    A)  \[a=0,b=0\]      

    B)  \[a=1,b=2\]

    C)  \[a=0,b\ne 0\]  

    D)         \[a=2,b=1\]

    E)  \[a=-2,b=-1\]

    Correct Answer: C

    Solution :

    The given differential equation is \[\frac{dy}{dx}=\frac{ax+h}{by+k}\] On integrating both sides.                 \[\int{(by+k)dy}=\int{(ax+h)}\,dx\] \[\Rightarrow \]               \[\frac{d{{y}^{2}}}{2}+ky=\frac{a{{x}^{2}}}{2}+hx+c\] Thus, above equation represents a parabola, if \[a=0\]and \[b\ne 0\]


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