CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2004

  • question_answer
    The     centre     of     the     ellipse \[9{{x}^{2}}+25{{y}^{2}}-18x-100y-116=0\]is:

    A)  (1, 1)                                    

    B) \[(-1,\text{ }2)\]

    C)  \[(-1,\text{ }1)\]          

    D)         (2, 2)

    E)  (1, 2)

    Correct Answer: E

    Solution :

    The given equation of ellipse is \[9{{x}^{2}}+25{{y}^{2}}-18x-100y-116=0\] \[\Rightarrow \]\[9{{x}^{2}}-18x+9+25{{y}^{2}}-100y+100-116\] \[-9-100=0\] \[\Rightarrow \]\[{{(3x-3)}^{2}}+{{(5y-10)}^{2}}=225\] \[\Rightarrow \]\[\frac{9{{(x-1)}^{2}}}{225}+\frac{25{{(y-2)}^{2}}}{225}=1\] \[\therefore \]Centre of ellipse is (1, 2).


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